Speed Time and Distance MCQ Quiz - Objective Question with Answer for Speed Time and Distance - Download Free PDF
Last updated on Apr 26, 2025
Latest Speed Time and Distance MCQ Objective Questions
Speed Time and Distance Question 1:
Ratio of speed of boat in still water and speed of stream is 7:2. Boat cover 120 km upstream in 8 hours and x km in 3 hours downstream. Find the value of x?
Answer (Detailed Solution Below)
Speed Time and Distance Question 1 Detailed Solution
Calculation
Speed of boat:stream = 7:2 ⇒ Let boat = 7x, stream = 2x
Upstream = 7x − 2x = 5x
Downstream = 7x + 2x = 9x
Upstream: 120 km in 8 hours ⇒ 15 km/hr ⇒ 5x = 15 ⇒ x = 3
Downstream speed = 9x = 27 km/hr
In 3 hrs: Distance = 27 × 3 = 81 km
Speed Time and Distance Question 2:
A boat can travel at a speed of 13 km/hr in still water. If the speed of the stream is 4 km per hour, find the time taken by the boat to travel 51 km downstream?
Answer (Detailed Solution Below)
Speed Time and Distance Question 2 Detailed Solution
Given:
Speed of the boat in still water = 13 km/hr
Speed of the stream = 4 km/hr
Distance to be travelled downstream = 51 km
Formula Used:
Downstream speed = Speed of the boat in still water + Speed of the stream
Time taken = Distance / Speed
Calculation:
Downstream speed = 13 + 4
Downstream speed = 17 km/hr
Time taken = 51 / 17
Time taken = 3 hours
The time taken by the boat to travel 51 km downstream is 3 hours.
Speed Time and Distance Question 3:
A car travelling at a speed of 80 km per hour can complete a journey in 9 hours. How long will it take to travel the same distance at 60 km per hour?
Answer (Detailed Solution Below)
Speed Time and Distance Question 3 Detailed Solution
Given:
Speed of the car = 80 km/hr
Time taken to complete the journey = 9 hours
Speed of the car for the same distance = 60 km/hr
Formula Used:
Distance = Speed × Time
Time = Distance / Speed
Calculation:
Distance travelled = 80 km/hr × 9 hrs
Distance travelled = 720 km
Time required to travel 720 km at 60 km/hr
⇒ Time = 720 km / 60 km/hr
⇒ Time = 12 hours
The correct answer is option 3.
Speed Time and Distance Question 4:
Three cars depart from a city at half-hour intervals, traveling in the same direction. After traveling for one hour, the third car meets the second one. This meeting happens half an hour after the third car meets the first one. If the distance between these meeting points is 30 km, calculate the speed (in km/h) of the second car relative to the first.
Answer (Detailed Solution Below)
Speed Time and Distance Question 4 Detailed Solution
Explanation:
Distance traveled by the first car in 1 1/2 hours
= Distance traveled by the third car in 1/2 hour ... (ii)
The third car covers 30 km in 1/2 hour.
∴ Speed of the third car = 60 km/h.
Using (i), the second car covers 60 km in 1 1/2 hours.
∴ Speed of the second car = 60 / 1.5 = 40 km/h.
Using (ii), the first car covers 30 km in 1 1/2 hours.
∴ Speed of the first car = 30 / 1.5 = 20 km/h.
Relative speed of the second car = 40 - 20 = 20 km/h.
Therefore, the required answer is 20.
Speed Time and Distance Question 5:
Speed of boat to that of speed of stream is 7 : 2. If the boat covers certain distance downstream in 1 hour then find the time(in minutes) taken by boat to cover the same distance in upstream.
Answer (Detailed Solution Below)
Speed Time and Distance Question 5 Detailed Solution
Given:
The speed of the boat to the speed of the stream is in the ratio 7 : 2.
The boat covers a certain distance downstream in 1 hour.
Let the speed of the boat be 7x and the speed of the stream be 2x.
Calculation:
The effective speed of the boat downstream is the sum of the boat's speed and the stream's speed:
Speed downstream = 7x + 2x = 9x
It is given that the boat covers a certain distance downstream in 1 hour. So, the distance covered downstream is:
Distance = Speed × Time = 9x × 1 = 9x
Now, to cover the same distance upstream, the effective speed of the boat is the difference between the boat's speed and the stream's speed:
Speed upstream = 7x - 2x = 5x
The time taken to cover the same distance upstream is:
Time = Distance / Speed = 9x / 5x = 9 / 5 hours
Converting the time to minutes (since 1 hour = 60 minutes):
Time in minutes = (9 / 5) × 60 = 108 minutes
∴ The time taken by the boat to cover the same distance upstream is 108 minutes.
Top Speed Time and Distance MCQ Objective Questions
A train of length 400 m takes 15 seconds to cross a train of length 300 m traveling at 60 km per hour from the opposite direction along a parallel track. What is the speed of the longer train, in km per hour?
Answer (Detailed Solution Below)
Speed Time and Distance Question 6 Detailed Solution
Download Solution PDFGiven
Length of first train (L1) = 400 m
Length of second train (L2) = 300 m
Speed of second train (S2) = 60 km/hr
Time taken to cross each other (T) = 15 s
Concept:
Relative speed when two objects move in opposite directions is the sum of their speeds.
Calculations:
Let the speed of the first train = x km/hr
Total length = 300 + 400
Time = 15 sec
According to the question:
700/15 = (60 + x) × 5/18
28 × 6 = 60 + x
x = 108 km/hr.
Therefore, the speed of the longer train is 108 km per hour.
Running at a speed of 60 km per hour, a train passed through a 1.5 km long tunnel in two minutes, What is the length of the train ?
Answer (Detailed Solution Below)
Speed Time and Distance Question 7 Detailed Solution
Download Solution PDFGiven:
Speed is 60 km per hour,
Train passed through a 1.5 km long tunnel in two minutes
Formula used:
Distance = Speed × Time
Calculation:
Let the length of the train be L
According to the question,
Total distance = 1500 m + L
Speed = 60(5/18)
⇒ 50/3 m/sec
Time = 2 × 60 = 120 sec
⇒ 1500 + L = (50/3)× 120
⇒ L = 2000 - 1500
⇒ L = 500 m
∴ The length of the train is 500 m.
A, B and C run simultaneously, starting from a point, around a circular track of length 1200 m, at respective speeds of 2 m/s, 4 m/s and 6 m/s. A and B run in the same direction, while C runs in the opposite direction to the other two. After how much time will they meet for the first time?
Answer (Detailed Solution Below)
Speed Time and Distance Question 8 Detailed Solution
Download Solution PDFGiven:
Total track length = 1200 m
Speed of A = 2 m/s ; speed of B = 4 m/s
Speed of C = 6 m/s
Formula used:
Distance = relative speed × time
Calculation:
Relative speed of A and B = (4 - 2) = 2 m/s
Relative speed of B and C = (6 + 4) = 10 m/s
Relative speed of A and C = (6 + 2) = 8 m/s
Time taken by A and B = 1200/2 = 600 sec
Time taken by B and C = 1200/10 = 120 sec
Time taken by A and C = 1200/8 = 150 sec
A, B and C will meet at = L.C.M {600,120, 150} = 600 sec = 600/60 = 10 minutes
∴ The correct answer is 10 minutes.
A man travels from A to B at a speed of 36 km/hr in 74 minutes and he travels a distance from B to C with a speed of 45 km/hr in 111 minutes. Find the average speed of whole journey.
Answer (Detailed Solution Below)
Speed Time and Distance Question 9 Detailed Solution
Download Solution PDFGiven:
A man travels from A to B at a speed of 36 km/hr in 74 minutes and he travels a distance from B to C with a speed of 45 km/hr in 111 minutes.
Formula used:
Average speed = Total distance/Total time taken
Calculation:
Time taken = 74 min : 111 min [given]
Ratio of Time taken = 2 : 3
Average Speed = \(\frac{{36\ \times\ 2\ +\ 45\ \times\ 3}}{{2\ +\ 3}}\)
Average Speed = 207/5
Average Speed = 41.4 km/hr
∴ The average speed of whole journey is 41.4 km/h
In a 1500 m race, Anil beats Bakul by 150 m and in the same race Bakul beats Charles by 75 m. By what distance does Anil beat Charles?
Answer (Detailed Solution Below)
Speed Time and Distance Question 10 Detailed Solution
Download Solution PDFGiven:
In a 1500 m race, Anil beats Bakul by 150 m and in the same race Bakul beats Charles by 75 m.
Concept used:
Time × Speed = Distance
Calculation:
According to the question,
Anil goes 1500m while Bakul goes (1500 - 150) i.e. 1350m.
Ratio of speed of Anil and Bakul = 1500 : 1350 = 10 : 9 = 200 : 180
According to the question,
Bakul goes 1500m while Charlie goes (1500 - 75) i.e. 1425m.
Ratio of speed of Bakul and Charlie = 1500 : 1425 = 20 : 19 = 180 : 171
So, the ratio of the speeds of Anil, Bakul and Charlie = 200 : 180 : 171
Let the speeds of Anil, Bakul and Charlie be 200k, 180k and 171k m/s respectively.
Time taken by Anil to finish the race = 1500/200k = 7.5/k seconds
Now, Anil beats Charlie by = (200 - 171)k ×7.5/k = 217.5m
∴ Anil beat Charlie by 217.5m.
Shortcut Trick
In a 1500 m race, Anil beats Bakul by 150 m
When Anil completes the race, Bakul covered (1500 - 150) = 1350 m
In a 1500 m race Charles is 75 m behind Bakul
So, in 1350 m race Charles is 75/1500 × 1350 = 67.5 m behind Bakul
So, Charles is (67.5 + 150) = 217.5 m behind from Anil in 1500 m race
∴ Anil beat Charlie by 217.5m.
A thief committed a crime and escaped from the spot at a speed of 12 m/h. A Security guard started chasing him 20 minutes after the thief started running and caught him in the next 20 minutes. What is the speed (in m/h) of the Security guard?
Answer (Detailed Solution Below)
Speed Time and Distance Question 11 Detailed Solution
Download Solution PDFConcept used:
Speed × time = distance
Calculation:
In the 1st 20 min the thief cover distance = 4 m,
20 min in hour = 20/60 hour
Let's assume that the speed of security guard = x m/hr, where x > 12
According to the question,
⇒ (x - 12) × 20/60 = 4
⇒ x - 12 = 12
⇒ x = 24
∴ The correct answer is 24 m/h
Geeta runs 5/2 times as fast as Babita. In a race, if Geeta gives a lead of 40 m to Babita, find the distance from the starting point where both of them will meet (correct up to two decimal places).
Answer (Detailed Solution Below)
Speed Time and Distance Question 12 Detailed Solution
Download Solution PDFGiven:
Geeta runs 5/2 times as fast as Babita
Geeta gives a lead of 40 m to Babita
Formula Used:
Distance = Speed × Time
Calculation:
Let the speed of Babita be 2x
⇒ Speed of Geeta = (5/2) × 2x = 5x
Let the distance covered by Geeta be y meters
⇒ Distance covered by Babita = (y - 40) meters
As time is constant, distance is directly proportional to speed
⇒ \(\frac{2x}{5x}\) = \(\frac{y-40}{y}\)
⇒ 2y = 5y - 200
⇒ y = 200/3 = 66.67m
∴ The distance from the starting point where both of them will meet is 66.67 m
A boat goes 20 km upstream and 44 km downstream in 8 hours. In 5 hours, it goes 15 km upstream and 22 km downstream. Determine the speed of the boat in still water.
Answer (Detailed Solution Below)
Speed Time and Distance Question 13 Detailed Solution
Download Solution PDFConcept used:
If upstream speed = U and downstream speed = D, then speed of boat = (U + D)/2
Calculation:
According to the question,
20/U + 44/D = 8 … (i)
15/U + 22/D = 5 … (ii)
Multiply by 2 the equation (ii) then subtract from 1 we get
20/U + 44/D = 8
30/U + 44/D = 10
- 10/U = - 2
⇒ U = 5 km/hr
Putting the value in equation (i), we get D = 11
So, the speed of boat = (U + D)/2 = (5 + 11)/2 = 8 km/hr
∴ The correct answer is 8 km/hr
Two trains, one 152.5 m long and the other 157.5 m long, coming from opposite directions crossed each other in 9.3 seconds. The combined speed of the two trains every hour would then be:
Answer (Detailed Solution Below)
Speed Time and Distance Question 14 Detailed Solution
Download Solution PDFGiven:-
Train1= 152.5m
Train2= 157.5m
Time = 9.3 sec
Calculation:-
⇒ Total distance to be covered = total length of both the trains
= 152. 5 + 157.5
= 310 m
Total time taken = 9.3 sec
Speed = distance/time
= (310/9.3) m/sec
= (310/9.3) × (18/5)
= 120 km/hr
∴ The combined speed of the two trains every hour would then be 120 km/hr.
Alternate Method When two trains are moving in opposite direction-
Let the speed of ine is 'v' and the second is 'u'
∴ Combined speed = v + u
Total distance = 152.5 + 157.5
= 310 m
∴ Combined speed = Total distance/total time
⇒ (v + u) = 310/9.3
⇒ (v + u) = 33.33 m/s
⇒ (v + u) = 33.33 × (18/5)
⇒ (v + u) = 120 km/hr
In a 900 metres race, Sathish beats Kiran by 270 metres and Rahul by 340 metres. By how many metres does Kiran beat Rahul in the same race?
Answer (Detailed Solution Below)
Speed Time and Distance Question 15 Detailed Solution
Download Solution PDFGiven,
Sathish completes 900 m race.
Kiran covers = 900 – 270 = 630 m
Rahul covers = 900 – 340 = 560 m
⇒ Ratio of their speed = 630/560
When Kiran covers 900 m race then
⇒ Rahul would cover = 900 × 560/630 = 800 m
∴ Kiran beats Rahul by = 900 – 800 = 100 m