Geeta runs 5/2 times as fast as Babita. In a race, if Geeta gives a lead of 40 m to Babita, find the distance from the starting point where both of them will meet (correct up to two decimal places).

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Question

This question was previously asked in

SSC CPO 2022 Tier-I Official Paper (Held On 10 Nov 2022 Shift 1) [Answer Key]

Answer 1

Given:

Geeta runs 5/2 times as fast as Babita

Geeta gives a lead of 40 m to Babita

Formula Used:

Distance = Speed × Time

Calculation:

Let the speed of Babita be 2x

⇒ Speed of Geeta = (5/2) × 2x = 5x

Let the distance covered by Geeta be y meters

⇒ Distance covered by Babita = (y - 40) meters

As time is constant, distance is directly proportional to speed

⇒ \(\frac{2x}{5x}\) = \(\frac{y-40}{y}\)

⇒ 2y = 5y - 200

⇒ y = 200/3 = 66.67m

∴ The distance from the starting point where both of them will meet is 66.67 m