Question
Download Solution PDFIn a family, three sons were born for every 3 years one after the other. If the ratio of present ages of father and the eldest son is 15:7 and the average of the present ages of the 3 sons is 18 years. What will be the ratio of the ages of the father and the youngest son after 5 years?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculations:
Let the present age of the eldest son be '7x' (from the ratio of father and eldest son's age).
The present age of the father = 15x.
The sum of the present ages of the 3 sons = 3 × 18 = 54 years.
Since the sons were born 3 years apart, the second son’s age = (7x - 3) and the youngest son’s age = (7x - 6).
Sum of the ages of the 3 sons = 7x + (7x - 3) + (7x - 6) = 54
⇒ 7x + 7x - 3 + 7x - 6 = 54
⇒ 21x - 9 = 54
⇒ 21x = 63
⇒ x = 3
Now, the present age of the eldest son = 7x = 7 × 3 = 21 years.
The present age of the father = 15x = 15 × 3 = 45 years.
The present age of the youngest son = (7x - 6) = 21 - 6 = 15 years.
Father's age after 5 years = 45 + 5 = 50 years.
Youngest son's age after 5 years = 15 + 5 = 20 years.
The ratio of their ages after 5 years = 50 : 20 = 5 : 2.
∴ The ratio of the father's age to the youngest son's age after 5 years is 5 : 2.
Last updated on Jul 3, 2025
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