पांच सिक्कों को एक बार उछाला जाता है। अधिक से अधिक चार पट (टेल) आने की प्रायिकता क्या है ?

This question was previously asked in
NDA 02/2022 Mathematics Official Paper (Held On 04 Sep 2022)
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Answer (Detailed Solution Below)

Option 1 :
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NDA 01/2025: English Subject Test
30 Qs. 120 Marks 30 Mins

Detailed Solution

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संकल्पना:

यदि A और B स्वतंत्र हैं, तो P(A और B) = P(A).P(B)

स्पष्टीकरण:

पाँच उछालों में अधिक से अधिक चार पट आने की प्रायिकता = 1 - सभी पाँच पट आने की प्रायिकता

⇒ पांच उछाल में अधिक से अधिक चार पट आने की प्रायिकता = 1 - P(T,T,T,T,T)

एक उछाल में, P(H) =  और P(T) = 

चूँकि सभी पाँच उछाल स्वतंत्र हैं,

⇒ P(T,T,T,T,T) =  ×  ×  ×  ×  = 

⇒पाँच उछालों में अधिकतम चार पट आने की प्रायिकता = 1 - ​​ = ​​​

∴ सही विकल्प (1) है।

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