Question
Download Solution PDFजर 180 मीटर लांबीची ट्रेन 9 सेकंदात खांब ओलांडते, तर ट्रेनचा वेग किलोमीटर/तासामध्ये शोधा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिलेल्याप्रमाणे:
ट्रेनची लांबी = 180 मीटर
वेळ = 9 सेकंद
वापरलेले सूत्र:
वेग = अंतर/वेळ
1 मीटर/सेकंद = 18/5 किमी/तास
गणना:
गती = 180/9 मीटर/सेकंद
⇒ (180/9) × (18/5) = 72 किमी/तास
∴ ट्रेनचा वेग 72 किलोमीटर/तास.
Last updated on Jun 17, 2025
-> The CUET 2025 provisional answer key has been made public on June 17, 2025 on the official website.
-> The CUET 2025 Postponed for 15 Exam Cities Centres.
-> The CUET 2025 Exam Date was between May 13 to June 3, 2025.
-> 12th passed students can appear for the CUET UG exam to get admission to UG courses at various colleges and universities.
-> Prepare Using the Latest CUET UG Mock Test Series.
-> Candidates can check the CUET Previous Year Papers, which helps to understand the difficulty level of the exam and experience the same.