In a cricket match, a batsman hits a sixes 8 times out of 32 balls played. The probability that a sixes is not hit in a ball:

Given:

A batsman hits a six 8 times out of 32 balls played.

Formula used:

Probability of an event = \(\dfrac{\text{Number of favorable outcomes}}{\text{Total number of outcomes}}\)

Calculations:

Probability of hitting a six = \(\dfrac{8}{32}\)

⇒ Probability of hitting a six = \(\dfrac{1}{4}\)

Probability of not hitting a six = 1 - Probability of hitting a six

⇒ Probability of not hitting a six = 1 - \(\dfrac{1}{4}\)

⇒ Probability of not hitting a six = \(\dfrac{3}{4}\)

∴ The correct answer is option 2.