If there are two springs A and B of stiffness K_A and K_B respectively, and if K_A > K_B, then on application of the same force, work done is more in

Explanation:

The work done by a spring is given by the equation:

\(W=\frac{1}{2}kx^2\)

where W is the work done, k is the stiffness of the spring, and x is the displacement of the spring from its equilibrium position.

If we apply the same force to both springs A and B, the displacement x will be different for each spring because the stiffness K_A is greater than K_B. This means that for the same force, spring A will be stretched or compressed less than spring B.

Since the work done is directly proportional to the square of the displacement, the spring with a larger displacement will do more work. In this case, since spring B has a larger displacement than spring A, the work done will be more in spring B.

Therefore, the correct option is 1.