यदि sin θ + cos θ = √3 है, तो tan θ  + cot θ किसके बराबर है। 

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Bihar STET TGT (Maths) Official Paper-I (Held On: 04 Sept, 2023 Shift 2)
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  1. 1
  2. 0
  3. \(\frac{2}{\sqrt3}\)
  4. \(\frac{1}{\sqrt3}\)

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Bihar STET Paper 1 Mathematics Full Test 1
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स्पष्टीकरण -

आइए त्रिकोणमितीय सर्वसमिकाओं का उपयोग करने के लिए दिए गए समीकरण \( \sin \theta + \cos \theta = \sqrt{3}\)  का वर्ग करें:

\( (\sin \theta + \cos \theta)^2 = (\sqrt{3})^2\)
\( \sin^2 \theta + 2 \sin \theta \cos \theta + \cos^2 \theta = 3\)

पायथागॉरियन सर्वसमिका का उपयोग करने पर \(\sin^2 \theta + \cos^2 \theta = 1\) :

\( 1 + 2 \sin \theta \cos \theta = 3 \\ 2 \sin \theta \cos \theta = 2 \\ \sin \theta \cos \theta = 1 \)

हम जानते हैं कि -

\(\tan \theta + \cot \theta = \frac{\sin \theta}{\cos \theta} + \frac{\cos \theta}{\sin \theta} \)

पायथागॉरियन सर्वसमिका का उपयोग करने पर \(\sin^2 \theta + \cos^2 \theta = 1\)  and \( \sin \theta \cos \theta = 1 :\)

\( \tan \theta + \cot \theta = \frac{1}{1} = 1 \)

अतः, \( \tan \theta + \cot \theta = 1 .\)

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