sin−1x का x के सापेक्ष अवकलज क्या है यदि वह अस्तित्व में है?

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Bihar STET Paper I: Mathematics (Held In 2019 - Shift 1)
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  1. \(\rm\frac{1}{\sqrt{1−x^2}}\)
  2. \(\rm\frac{1}{\sqrt{x^2−1}}\)
  3. \(\rm\frac{1}{\sqrt{1+x^2}}\)
  4. इनमें से कोई नहीं

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Option 1 : \(\rm\frac{1}{\sqrt{1−x^2}}\)
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Bihar STET Paper 1 Mathematics Full Test 1
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दिया गया है:

फलन: sin-1(x)

प्रयुक्त अवधारणा:

x के सापेक्ष व्युत्क्रम त्रिकोणमितीय फलनों के अवकलज को श्रृंखला नियम का उपयोग करके ज्ञात किया जाता है।

d/dx(sin-1x) = 1 / √(1 - x2)

गणना:

अवकलज के लिए सूत्र लागू करने पर:
  
d/dx(sin-1x) = 1 / √(1 - x2)

⇒ d/dx(sin-1x) = 1 / √(1 - x2)

∴ x के सम्बन्ध में syn-1(x) का अवकलज \(\rm\frac{1}{\sqrt{1−x^2}}\) है।

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