Question
Download Solution PDFWhat is the smallest number that can be added to 9454351626 so that it becomes divisible by 11?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
Sum of the numbers of odd place is 9 + 5 + 3 + 1 + 2 = 20
Sum of the digits of even place is, 4 + 4 + 5 + 6 + 6 = 25
Thus, the difference becomes 25 - 20 = 5
So, we will add 6 as 6 + 5 = 11.
∴ The number 6 should be added to 9454351626 to make it divisible by 11.
Last updated on Jul 21, 2025
-> NTA has released UGC NET June 2025 Result on its official website.
-> SSC Selection Post Phase 13 Admit Card 2025 has been released at ssc.gov.in
-> The SSC CGL Notification 2025 has been announced for 14,582 vacancies of various Group B and C posts across central government departments.
-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025 in multiple shifts.
-> Candidates had filled out the SSC CGL Application Form from 9 June to 5 July, 2025. Now, 20 lakh+ candidates will be writing the SSC CGL 2025 Exam on the scheduled exam date. Download SSC Calendar 2025-25!
-> In the SSC CGL 2025 Notification, vacancies for two new posts, namely, "Section Head" and "Office Superintendent" have been announced.
-> Candidates can refer to the CGL Syllabus for a better understanding of the exam structure and pattern.
-> The CGL Eligibility is a bachelor’s degree in any discipline, with the age limit varying from post to post.
-> The SSC CGL Salary structure varies by post, with entry-level posts starting at Pay Level-4 (Rs. 25,500 to 81,100/-) and going up to Pay Level-7 (Rs. 44,900 to 1,42,400/-).
-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.
-> NTA has released the UGC NET Final Answer Key 2025 June on its official website.