What is the smallest number that can be added to 9454351626 so that it becomes divisible by 11?

This question was previously asked in
SSC CGL 2023 Tier-I Official Paper (Held On: 21 Jul 2023 Shift 4)
View all SSC CGL Papers >
  1. 1
  2. 6
  3. 5
  4. 4

Answer (Detailed Solution Below)

Option 2 : 6
super-pass-live
Free
SSC CGL Tier 1 2025 Full Test - 01
3.3 Lakh Users
100 Questions 200 Marks 60 Mins

Detailed Solution

Download Solution PDF

Calculation:

Sum of the numbers of odd place is 9 + 5 + 3 + 1 + 2 = 20

Sum of the digits of even place is, 4 + 4 + 5 + 6 + 6 = 25

Thus, the difference becomes 25 - 20 = 5

So, we will add 6 as 6 + 5 = 11.

The number 6 should be added to 9454351626 to make it divisible by 11.

Latest SSC CGL Updates

Last updated on Jul 11, 2025

-> The SSC CGL Application Correction Window Link Live till 11th July. Get the corrections done in your SSC CGL Application Form using the Direct Link.

-> This year, the Staff Selection Commission (SSC) has announced approximately 14,582 vacancies for various Group B and C posts across government departments.

-> The SSC CGL Tier 1 exam is scheduled to take place from 13th to 30th August 2025.

->  Aspirants should visit ssc.gov.in 2025 regularly for updates and ensure timely submission of the CGL exam form.

-> Candidates can refer to the CGL syllabus for a better understanding of the exam structure and pattern.

-> The CGL Eligibility is a bachelor’s degree in any discipline.

-> Candidates selected through the SSC CGL exam will receive an attractive salary. Learn more about the SSC CGL Salary Structure.

-> Attempt SSC CGL Free English Mock Test and SSC CGL Current Affairs Mock Test.

-> The RRB Railway Teacher Application Status 2025 has been released on its official website.

Get Free Access Now
Hot Links: teen patti 100 bonus teen patti joy 51 bonus teen patti master apk best teen patti all teen patti glory