Two resistors, each of 10 Ω, are connected in parallel. This combination is then connected in series with a third 10 Ω resistor and a 6 V battery. The current in the circuit is ______.

Concept:

• Ohm's law: It states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions and temperature, remain constant.
• Mathematically, current-voltage can be written as V = IR, where V = Voltage, I = Current, R = Resistance
• For equivalent resistance in parallel combinations
  • \(\frac{1}{R_{eq}}=\frac{1}{R_1}+\frac{1}{R_2}\)

• For equivalent resistance in series combinations

  • ​R_eq = R₁ + R₂ + . . . . + R_n

_​

Calculation:

Two resistors, each of 10 Ω, are connected in parallel. This combination is then connected in series with a third 10 Ω resistor and a 6 V battery. The current in the circuit is ______.

Given, Resistance, R₁ = 10 Ω, R₂ = 10 Ω, Battery, V = 6 volt

The resistor is connected in parallel combination,

In parallel combination, \(\frac{1}{R_p}=\frac{1}{R_1}+\frac{1}{R_2}\)

\(\frac{1}{R_p}=\frac{1}{10}+\frac{1}{10}\)

R_P = 5 Ω 

Now, the resistance R_P is connected in series with 10 Ω,

R_eq = 5 + 10 = 15 Ω 

Current in the circuit, \(I=\frac{V}{R}=\frac{6}{15}=0.4~A\)