Question
Download Solution PDFThe voltage gain in a common emitter configuration is:
This question was previously asked in
KVS TGT WET (Work Experience Teacher) Official Paper
Answer (Detailed Solution Below)
Option 3 : \(\rm -\frac{hfeR_L}{R_i}\)
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KVS TGT Mathematics Mini Mock Test
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Detailed Solution
Download Solution PDFConcept:
Voltage gain \(= {A_v} = \frac{{{V_2}}}{{{V_i}}} = \frac{{{I_L}{R_L}}}{{{V_i}}}\)
\({A_v} = \frac{{ - {h_{fe}}{I_b}{R_L}}}{{{V_i}}} = \frac{{ - hfe{R_L}}}{{{R_i}}}\)
\(\left( {\because{R_i} = \frac{{{I_b}}}{{{V_i}}}} \right)\)
\({A_v} = \frac{{ - {h_{fe}}{R_L}}}{{{R_i}}}\)
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