The voltage gain in a common emitter configuration is:

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  1. \(\rm -\frac{hfeR_L}{R_o}\)
  2. -hfe 
  3. \(\rm -\frac{hfeR_L}{R_i}\)
  4. hie + (1 + hfe) Re

Answer (Detailed Solution Below)

Option 3 : \(\rm -\frac{hfeR_L}{R_i}\)
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Concept:

SSC JE Electrical 104 12Q Basic Electronics QBank 2(Hindi) - Final.docx 2

Voltage gain \(= {A_v} = \frac{{{V_2}}}{{{V_i}}} = \frac{{{I_L}{R_L}}}{{{V_i}}}\)

\({A_v} = \frac{{ - {h_{fe}}{I_b}{R_L}}}{{{V_i}}} = \frac{{ - hfe{R_L}}}{{{R_i}}}\)

\(\left( {\because{R_i} = \frac{{{I_b}}}{{{V_i}}}} \right)\)

\({A_v} = \frac{{ - {h_{fe}}{R_L}}}{{{R_i}}}\)

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