The total bond order between adjacent carbon atoms of benzene is

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CSIR-UGC (NET) Chemical Science: Held on (26 Nov 2020)
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  1. 0.5
  2. 2
  3. 1.5
  4. 2.5

Answer (Detailed Solution Below)

Option 3 : 1.5
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Detailed Solution

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Concept:

Bond order:

  • Bond order is the number of bonding pairs of electrons between two atoms.
  • In a covalent bond; a single bond has a bond order of one, a double bond has a bond order of two, and a triple bond has a bond order of 3
  • Nonbonding electrons and antibonding electrons are not considered for the determination of the bond order.

Bond order

= \({{\left( {{\rm{Number\; of\; electrons\; in\; BMO - Number\;of\; electrons\; in\; ABMO}}} \right)} \over {\rm{2}}}\).

Explanation:

  • The molecular formula of benzene is C6H6. Benzene has 6 C-C single bond. For each C-C single bond, it has 2 bonding electrons. B.O for each C-C single bond

 \( = {{\left( {2 - 0} \right)} \over {\rm{2}}}\)

\( = 1\)

  • Benzene has a 6 pi molecular orbital
  • The number of electrons in the pi-bonding molecular orbital of benzene is 6. While there are no electrons in the antibonding molecular orbital.
  • Thus, for benzene the pi bond order

\( = {{\left( {6 - 0} \right)} \over {\rm{2}}}\)

\( = 3\)

  • This is the pi bond order for 6 C-C bonds.
  • The bond order for each C-C bond in benzene is

\( = 1 + 0.5\)

\( = 1.5\)

Conclusion:

Hence, the total bond order between adjacent carbon atoms of benzene is 1.5

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