Question
Download Solution PDFThe present population of a town is 6000, if the number of males increase by 8% and the number of females increase by 10%, the population will be 6500, Find the present number of females in the town -
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
The population of a town = 6000
Calculation:
Let, the number of males = m
The number of females, f = 6000 - m
According to the question,
If the number of males increases by 8% and the number of females increases by 10%,
⇒ 8% of m + 10 % of f = 6500 - 6000 = 500
⇒ \(\dfrac{8}{100}\) × m + \(\dfrac{10}{100}\) × (6000 - m) = 500
⇒ 8m + 60000 - 10m = 500 × 100
⇒ 2m = 60000 - 50000 = 10000
⇒ m = \(\dfrac{10000}{2}\) = 5000
The number of females, f = 6000 - m
⇒ 6000 - 5000 = 1000
∴ The present number of females in the town is 1000.
Last updated on Feb 12, 2025
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