The Poynting vector of an electromagnetic wave in vacuum is:

S = {(120 W/m2) sin2[(8.0 rad/m) z + (6.28 × 109 rad/s) t]} k

What is the frequency of the wave?

  1. 10 MHz
  2. 100 MHz
  3. 1000 MHz
  4. 10 Hz

Answer (Detailed Solution Below)

Option 3 : 1000 MHz
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Detailed Solution

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Concept:

  • Poynting vector represents the directional energy flux (the energy transfer per unit area per unit time) of an electromagnetic field.
  • The SI unit of the Poynting vector is the watt per square meter(w/m2).
  • It is named after its discovery John Henry Poynting who first derived it in 1884.

 

The general expression of a wave propagating in the z-direction is given by:

\(P\left( {z,t} \right) = {P_{max}}\cos \left( {kz - ω t + \phi } \right)\)

k = wave number

ω = frequency (in rad)

Calculation: 

Given Poynting vector of an electromagnetic wave in a vacuum:

S = {(120 W/m2) sin2[(8.0 rad/m) z + (6.28 × 109 rad/s) t]} k

Comparing this with the general expression, the angular frequency of the wave will be:

\(ω= 2\pi f\)

Here angular frequency(ω) is equal to 6.28×10rad/s.

\(f=\frac{ω}{2\pi}\)

\(f=\frac{6.28 \times10^{9}}{2\times 3.14}\)

\(f=\frac{2 \times10^{9}}{2}\)

\(f=10^{9}=1000\times 10^{6} \)

Since 1 MHz = 106 Hz

f = 1000 MHz

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