The centre-tapped full wave rectifier's efficiency is ______.

Full wave rectifier

Case 1: During +ve half

D_o ON and D₁ OFF

V_o = V_s

Case 2: During -ve half

Do OFF and D1 ON

Vo = -Vs

The output waveform is:

The rectification efficiency is the ratio of the DC output power to the AC input power. 

\(V_{o(avg)}={2V_m\over \pi}\) and \(I_{o(avg)}={2V_m\over \pi R}\)

\(V_{o(rms)}={V_m\over \sqrt{2}}\) and \(I_{o(rms)}={V_m\over \sqrt{2}R}\)

% η = \({V_{o(avg)}\times I_{o(avg)}\over V_{o(rms) \times I_{o(rms)}}}\)

% η = \({{2V_m\over \pi}\times{2V_m\over \pi R}\over {V_m\over \sqrt{2}}\times {V_m\over \sqrt{2}R}}\)

% η = 81.2%

Mistake Points The rectification efficiency of half wave rectifier is 40.6%