Question
Download Solution PDFఒక చతుస్త్రం యొక్క కర్ణం 10√ 2 సెం.మీ., దాని చుట్టుకొలతను కనుగొనండి?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFపై బొమ్మ నుండి చూసినట్లుగా,
కర్ణం AC = 10√2
ఇప్పుడు AB = BC తో ABC లంబ కోణ త్రిభుజాన్ని ఏర్పరుస్తుంది
పైథాగరస్ సిద్ధాంతం ద్వారా,
AB2 + BC2 = AC2
2AB2= 100 × 2
AB2 = 100
AB = 10
చతుస్త్రం చుట్టుకొలత = 4 AB = 40 సెం.మీ.
ప్రత్యామ్నాయ పరిష్కారం:
చతుస్త్రం యొక్క భుజం "A" ఐన
కర్ణం = a√2
అందువల్ల, a√2 = 10√2
⇒ భుజం = a = 10
చతుస్త్రం చుట్టుకొలత = 4a
∴ చతుస్త్రం చుట్టుకొలత = 40 సెం.మీ.
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