Question
Download Solution PDFPQRS is a rhombus. The each sides of it is 40 cm. If PR = 64 cm and QS = (8x + 8). Then, the value of x is -
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFPR = 64 cm
Thus, PO = RO = 32 cm
QS = (8x + 8) cm
Thus, QO = OS = (4x + 4) cm
In Δ SOR –
\(S{R^2} = S{O^2} + R{O^2}\)
⇒ \({40^2} = {\left( {4{\rm{x}} + 4} \right)^2} + {\left( {32} \right)^2}\)
⇒ 402 – 322 = (4x + 4)2
⇒ 4x + 4 = 24
⇒ 4x + 4 = 24
⇒ 4x = 20
⇒ x = 5 cm
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