Question
Download Solution PDF4π चौ.सेमी. क्षेत्रफळाच्या पायाच्या आणि 12π घनसेमी. आकारमानाच्या लहान शंकूला 16π चौ.सेमी. क्षेत्रफळाच्या पायाच्या आणि 96π घनसेमी. आकारमानाच्या मोठ्या शंकूच्या वरून कापले जाते. उर्वरित घन आकृतीची उंची काढा.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF∵ शंकूचे क्षेत्रफळ = π(त्रिज्या)2 आणि शंकूचे आकारमान = (1/3)π x (त्रिज्या)2 x उंची
⇒ शंकूचे आकारमान = (1/3) x पायाचे क्षेत्रफळ x उंची
आता, लहान शंकूचे आकारमान = 12π घनसेमी.
⇒ 12π = 1/3 x 4π x उंची
⇒ लहान शंकूची उंची = 9 सेमी
अशाच प्रकारे, मोठ्या शंकूचे आकारमान = 96π घनसेमी.
⇒ 96π = 1/3 x 16π x उंची
⇒ मोठ्या शंकूची उंची = 18 सेमी
∴ उर्वरित घन आकृतीची उंची = मोठ्या शंकूची उंची - लहान शंकूची उंची = 18 - 9 = 9 सेमी
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