Question
Download Solution PDFPAQ എന്നത് അതിലെ A എന്ന ബിന്ദുവിലെ കേന്ദ്രം O ഉള്ള, ഒരു വൃത്തത്തിലേക്കുള്ള സ്പർശരേഖയാണ്. AB എന്നത് ∠BAQ = x° (x <90°) എന്ന തരത്തിലുള്ള ഒരു ഞാൺ ആണ്. C എന്നത് പ്രധാന ചാപം AB-യിലെ ഒരു ബിന്ദുവാണ്, അതായത് ∠ACB = y°. ∠ABO = 32° ആണെങ്കിൽ, x + y യുടെ മൂല്യം ഇതാണ്:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDF∠ABO = 32°, ∠BAQ = X and ∠ACB = Y
∠ABO = ∠BAO = 32° [OA = OB]
∠OAQ = 90° [സ്പർശരേഖ]
∠OAQ = ∠BAO + ∠BAQ
⇒ 90° = 32° + x
⇒ x = 90° - 32° = 58°
നമുക്കറിയാവുന്നത് പോലെ,
x = y = 58°
⇒ x + y = 58° + 58°
⇒ x + y = 116°
Last updated on Jun 11, 2025
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