Maximum percent rectifier efficiency of half wave rectifier is :

This question was previously asked in
MPPKVVCL Jabalpur JE Electrical 16 August 2018 Official Paper
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  1. 10.1 
  2. 80.2
  3. 20.3
  4. 40.6

Answer (Detailed Solution Below)

Option 4 : 40.6
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The correct option is 4

Concept:

Half wave rectifier

F1 S.B Madhu 20.01.20 D1

A half-wave rectifier converts an AC signal to DC by passing either the negative or positive half-cycle of the waveform and blocking the other. Half-wave rectifiers can be easily constructed using only one diode, but are less efficient than full-wave rectifiers.

The maximum efficiency of a half-wave rectifier is 40.6%. The proportion of dc output power to input power is used to define a rectifier's efficiency.

A half-wave rectifier's efficiency will be:

\(\eta = \frac{P_{DC}}{P_{AC}}=\frac{\frac{V_{DC^{2}}}{R_{L}}}{\frac{V_{RMS^{2}}}{R_{L}}} = \frac{V_{DC^{2}}}{V_{AC^{2}}}\)

VDC = DC voltages

VAC = AC voltages

\(V_{DC}= \frac{V_{M}}{\Pi }\)

\(V_{AC}= \frac{V_{M}}{2}\)

Calculation

\(​​​​\eta =\frac{2^{2}}{\Pi ^{2}} = 40.6\)

 

Additional InformationFull wave rectifier

F4 Vinanti Engineering 21.12.22 D6

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