Question
Download Solution PDFLet ABCDEF be a regular hexagon. If \(\rm \vec{AD}=m \vec {BC}\ and\ \vec {CF}=n\vec {AB}\) then what is mn equal to
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFCalculation:
\( \vec{AB} = 2\vec{FC} \)
⇒ \( \vec{AB} = -2\vec{CF} \)
⇒ \( n = -\frac{1}{2} \)
Also,
\( \vec{AD} = 2\vec{BC} \Rightarrow m = 2 \)
Now,
\( mn = 2 \left( -\frac{1}{2} \right) = -1 \)
∴ The final value of is -1.
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