Question
Download Solution PDFIn three containers - yellow, white and black, 120 marbles are placed. There are twice as many marbles in the white and yellow containers combined as there are in the black container. Also, there are twice as many marbles in the black container as there are in the yellow container. How many marbles are there in the white container?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
1) In three containers - yellow, white, and black, 120 marbles are placed.
Let the total number of marbles in the white container be = W
Let the total number of marbles in the yellow container be = Y
Let the total number of marbles in the black container be = B
So, B + Y + W = 120
2) There are twice as many marbles in the white and yellow containers combined as there are in the black container.
Y + W = 2B
3) There are twice as many marbles in the black container as there are in the yellow container.
B = 2Y
Now, substituting the value of B from the point 3 in the equation of point 2:
Y + W = 2B ⇒ Y + W = 2(2Y)
⇒ Y + W = 4Y
⇒ W = 3Y
Now, substituting the value of B and W in the equation of point 1:
B + Y + W = 120 ⇒ 2Y + Y + 3Y = 120
⇒ 6Y = 120
⇒ Y = 20
Putting the value of Y:
W = 3Y ⇒ W = 3(20)
⇒ W = 60
Therefore, the total number of marbles in the white container is 60.
Hence, "Option 4" is the correct answer.
Last updated on Jun 11, 2025
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