Question
Download Solution PDFIn the under-damped vibrating system, the amplitude of vibration-
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
If the system is underdamped, it will swing back and forth with decreasing size of the swing until it comes to a stop. Its amplitude will decrease exponentially.
\(x\left( t \right) = {e^{ - \xi {\omega _n}t}}\left( {A{e^{i{\omega _d}t}} + B{e^{ - i{\omega _d}t}}} \right)\)
Important Points
Overdamped System: ζ > 1
\(x(t) = A{e^{( - \xi + \sqrt {{\xi ^2} - 1} ){ω _n}t}} + B{e^{( - \xi - \sqrt {{\xi ^2} - 1} ){ω _n}t}}\)
This is the equation of aperiodic motion i.e. the system cannot vibrate due to over-damping. The magnitude of the resultant displacement approaches zero with time.
Underdamped: ζ < 1
\(x\left( t \right) = {e^{ - \xi {ω _n}t}}\left( {A{e^{i{ω _d}t}} + B{e^{ - i{ω _d}t}}} \right)\)
\(x(t) = A{e^{ - \xi {ω _n}t}}\sin ({ω _d} + \phi )\)
This resultant motion is oscillatory with decreasing amplitudes having a frequency of ωd. Ultimately, the motion dies down with time.
Critical Damping: ζ = 1
\(x(t) = (A + Bt){e^{ - {\omega _n}t}}\)
The displacement will be approaching to zero with shortest possible time.
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