Question
Download Solution PDFIn the full-wave rectifier, relation between peak value and rms value is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFThe RMS or the effective value of a waveform f(t) is given by:
\({f_{rms}} = \sqrt {\frac{1}{T}\mathop \smallint \limits_0^T {f^2}\left( t \right)dt}\)
Application:
The relation between the peak value and rms value of the waveform is given as:
\(V_p=\sqrt{2} V_{rms}\)
The relation between the peak value and the average value for a half and full-wave rectifier is:
\({V_{avg}} = \frac{{{V_m}}}{\pi }\) for half-wave rectifier
\({V_{avg}} = \frac{{2{V_m}}}{\pi }\) for full-wave rectifier
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