If the virtual memory size is 32 MB and a physical memory size is 4MB with a page size of 2KB, Calculate the number of frames available in physical memory

  1. 1024
  2. 2048
  3. 3072
  4. 4096

Answer (Detailed Solution Below)

Option 2 : 2048

Detailed Solution

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The correct answer is Option 2.

Key Points

  • If the virtual memory size is 32 MB and the physical memory size is 4 MB with a page size of 2 KB, we need to calculate the number of frames available in physical memory.
  • Calculation:
    • First, convert the physical memory size into kilobytes (KB):
      • 4 MB = 4 * 1024 KB = 4096 KB
    • Next, divide the physical memory size by the page size to get the number of frames:
      • Number of frames = Physical Memory Size / Page Size
      • Number of frames = 4096 KB / 2 KB = 2048 frames
  • Therefore, the number of frames available in physical memory is 2048.

Additional Information

  • Virtual Memory:
    • Virtual memory allows a computer to compensate for shortages of physical memory by temporarily transferring data from random access memory (RAM) to disk storage.
    • It uses both hardware and software to enable a computer to run larger applications or multiple applications simultaneously.
  • Physical Memory:
    • Physical memory refers to the actual RAM installed in a computer.
    • It is a volatile memory that temporarily stores data and machine code currently being used.
  • Page Size:
    • Page size is the size of a page in memory management schemes. It is a fixed-length contiguous block of virtual memory.
    • Page sizes are typically a power of 2, ranging from 512 bytes to several megabytes.
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