If the capacitance between two conductors of a 3 phase line is 6 μF, the capacitance of each conductor to neutral will be

This question was previously asked in
WBPSC JE Electrical 2018 (Held on 18th Feb 2018) Official Paper
View all WBPSC JE Papers >
  1. 3 μF
  2. 12 μF
  3. 6 μF
  4. 1.5 μF

Answer (Detailed Solution Below)

Option 2 : 12 μF
Free
WBPSC JE Civil Soil Mechanics Mock Test
4.9 K Users
20 Questions 40 Marks 25 Mins

Detailed Solution

Download Solution PDF

The correct answer is option  2):(12 μF)

Concept:

If the capacitance between two conductors A,B of a 3-phase line is given as CAB

The capacitance of each conductor to neutral will be CAN,CBN which is also called phase capacitance

CAN or CBN = 2 × CAB

Calculation:

Given 

CAB =  6 μF

CAN or CBN = 2 × CAB

= 2 × 6

= 12  μF

Latest WBPSC JE Updates

Last updated on Jun 24, 2025

-> WBPSC JE recruitment 2025 notification will be released soon. 

-> Candidates with a Diploma in the relevant engineering stream are eligible forJunior Engineer post. 

-> Candidates appearing in the exam are advised to refer to the WBPSC JE syllabus and exam pattern for their preparations. 

-> Practice WBPSC JE previous year question papers to check important topics and chapters asked in the exam.

More Transmission and Distribution Questions

Get Free Access Now
Hot Links: teen patti - 3patti cards game downloadable content teen patti casino apk teen patti real cash 2024