If current = 1.414 A and resistance = 50 Ω, then find power.

This question was previously asked in
RRB ALP Electronics Mechanic 21 Jan 2019 Official Paper (Shift 3)
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  1. 400 Watts
  2. 100 Watts
  3. 300 Watts
  4. 200 Watts

Answer (Detailed Solution Below)

Option 2 : 100 Watts
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Detailed Solution

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Concept

The power across a resistance is:

\(P=I^2R\)

where, P = Power

I = Current

R = Resistance

Calculation

Given, I = 1.414 A

R = 50 Ω 

P = (1.414)2 × 50

P = 100 watt

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