Question
Download Solution PDFIf A = \(\left[ \begin{matrix} 2 & x-3 & x-2 \\ 3 & -2 & -1 \\ 4 & -1 & -5 \\ \end{matrix} \right]\) is a symmetric matrix then x
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
Symmetric Matrix:
- Square matrix A is said to be symmetric if the transpose of matrix A is equal to matrix A itself
- AT = A or A’ = A
Where, AT or A’ denotes the transpose of matrix
- A square matrix A is said to be symmetric if aij = aji for all i and j
Where aij and aji is an element present in matrix.
Calculation:
Given:
A is a symmetric matrix,
⇒ AT = A or aij = aji
A = \(\left[ \begin{matrix} 2 & x-3 & x-2 \\ 3 & -2 & -1 \\ 4 & -1 & -5 \\ \end{matrix} \right]\)
So, by property of symmetric matrices
⇒ a12 = a21
⇒ x – 3 = 3
∴ x = 6Last updated on May 30, 2025
->UPSC has released UPSC NDA 2 Notification on 28th May 2025 announcing the NDA 2 vacancies.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced for cycle 2. The written examination will be held on 14th September 2025.
-> Earlier, the UPSC NDA 1 Exam Result has been released on the official website.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.