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NDA (Held On: 18 Apr 2021) Maths Previous Year paper
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  1. 0
  2. 1
  3. 2 tanθ
  4. 2 cotθ

Answer (Detailed Solution Below)

Option 1 : 0
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संकल्पना:

त्रिकोणमितीय सूत्र

sec2 θ = 1 + tan2 θ

cosec2 θ = 1 + cot2 θ

cot θ = 

sec θ = 

cosec θ = 

 

गणना:

= tan2 θ - (-tan θ)2

= tan2 θ - tan2 θ 

= 0

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