Question
Download Solution PDF\(\rm \frac{3(cosec^2 \,26^\circ-tan^2\,64^\circ)+(cot^2\,42^\circ-sec^2\,48^\circ)}{cot(22^\circ-\theta)-cosec^2(62^\circ+\theta)-tan(\theta+68^\circ)+tan^2(28^\circ-\theta)}\) का मान क्या है?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
\(\rm \frac{3(cosec^2 \,26^\circ-tan^2\,64^\circ)+(cot^2\,42^\circ-sec^2\,48^\circ)}{cot(22^\circ-θ)-cosec^2(62^\circ+θ)-tan(θ+68^\circ)+tan^2(28^\circ-θ)}\)
प्रयुक्त सूत्र:
1 + tan2θ = sec2θ
⇒ tan2θ – sec2θ = -1
1 + cot2θ = cosec2θ
⇒ cot2θ – cosec2θ = -1
गणना:
\(\rm \frac{3(cosec^2 \,26^\circ-tan^2\,64^\circ)+(cot^2\,42^\circ-sec^2\,48^\circ)}{cot(22^\circ-θ)-cosec^2(62^\circ+θ)-tan(θ+68^\circ)+tan^2(28^\circ-θ)}\)
θ = 0° रखें क्योंकि के लिए कोई शर्त नहीं है
⇒ \(\rm \frac{3(sec^2 \,64^\circ-tan^2\,64^\circ)+(tan^2\,48^\circ-sec^2\,48^\circ)}{tan68^\circ-cosec^262^\circ-tan68^\circ+cot^262^\circ}\)
⇒ \(\rm \frac{3(1)+(-1)}{-cosec^262^\circ+cot^262^\circ}\)
⇒ \(\rm \frac{3-1}{-1}\)
⇒ \(\rm \frac{2}{-1}\)
⇒ –2
∴ अभीष्ट मान –2 है।
Last updated on Jul 14, 2025
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