Question
Download Solution PDF50 mA के भार कर्षण से जुड़े 100 μF वाले निस्यन्दक संधारित्र के साथ पूर्ण-तरंग दिष्टकारी की उर्मिका वोल्टता ________ होगी।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFसंकल्पना
पूर्ण तरंग दिष्टकारी की उर्मिका वोल्टता को निम्न द्वारा दिया गया है:
\(V_R={2.4V_{dc}\over R_LC}\)
∵ \({V_{dc}\over R_L}=I_L\)
\(V_R={2.4I_{L}\over C}\)
जहाँ, VR = उर्मिका वोल्टता
IL = भार धारा
C = संधारित्र
गणना
दिया गया है,
C = 100 μF
IL = 50 mA
\(V_R={2.4\times 50\times 10^{-3}\over 100\times 10^{-6}}\)
VR = 1.2 kV
Last updated on May 29, 2025
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