Question
Download Solution PDF500 kW/m2 के ऊर्जा प्रवाह के साथ प्रकाश 10 cm की त्रिज्या के साथ एक गैर-प्रतिबिंबित गोलाकार पृष्ठ पर सामान्य घटना पर 5 min तक गिरता है। इस पृष्ठ पर प्रदत्त कुल संवेग का परिमाण ______ है।
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFदिया गया है:
\(Time=5minutes=300s\) ,
\(Radius(r)\text{ of a circular surface }=10cm=10\times10^{-2}=10^{-1}m\)
\(\text{ Energy Flux }, S=500kW/m^2=500\times10^3W/m^2\)
अवधारणा:
प्रति इकाई समय में तरंग के लंबवत तल से गुजरने वाली प्रति इकाई क्षेत्र की ऊर्जा को विद्युत फ्लक्स कहा जाता है, जिसे S द्वारा निरूपित किया जाता है।
- \(S=\frac{E}{tA}=\frac{E}{\pi r^2t}\)
- \(E=S.\pi r^2.t\)
- संवेग \(p=\frac{E}{c}\)
स्पष्टीकरण:
- \(E=S.\pi r^2.t=500\times10{^3}\times 300 \times \pi \times(10^{-1})^2 \)
- \(E=15\pi\times10^5J\)
संवेग
है।
Last updated on Jun 19, 2025
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