Consider the following statements:

When compared with a bridge rectifier, a centre-tapped full wave rectifier:

i. Has larger transformer utilization factor.

ii. Can be used for floating output terminals i.e. no input terminal is grounded.

iii. Needs two diodes instead of four.

iv. Needs diodes of a lower PIV rating.

Which of the above statements are correct?

Question

Question

This question was previously asked in

ESE Electronics 2010 Paper 2: Official Paper

Attempt Online

Answer 1

Concept:

Parameter	Centre Tapped FWR	Bridge rectifier
D.C diode Voltage	\({\left( {{V_{dc}}} \right)_{diode}} = \frac{{2{V_m}}}{\pi }\)	\({\left( {{V_{dc}}} \right)_{Diode}} = \frac{{{V_m}}}{\pi }\)
Peak inverse voltage(PIV)	2V_m	V_m
Transformer utilization factor	\(0.576\left[ {\frac{{{R_L}}}{{{R_L} + {R_1}}}} \right]\)	\(0.81\left[ {\frac{{{R_L}}}{{2{R_F} + {R_L}}}} \right]\)

Definition:

Peak Inverse Voltage (PIV):

“It is the maximum voltage that diode can face under the Reverse Bias condition”.

Transformer utilization factor(TUF):

“It is the ratio of DC output power to AC rating of secondary winding”

i.e., \(TUF = \frac{{D.C.\;\;Output\;power}}{{AC\;rating\;of\;secondary\;winding}}\)