An RL circuit has a resistance of 3 ohms and a reactance of 4 ohms, the impedance of the circuit is

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VSSC (ISRO) Technician B (Electronic Mechanic) 2012 Official Paper (Held on 22 Dec 2012)
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  1. 5 ohms
  2. 7 ohms
  3. 1 ohm
  4. 1.33 ohms

Answer (Detailed Solution Below)

Option 1 : 5 ohms
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Detailed Solution

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Concept:

For a series RL circuit, the net impedance is given by:

Z = R + j (XL)

XL = Inductive Reactance given by:

XL = ωL

The magnitude of the impedance is:

\(|Z|=\sqrt{R^2+X_L^2}\)

Calculation:

With R = 3 Ω and XL = 4 Ω, we get:

\(|Z|=\sqrt{(3)^2+(4)^2}\)

\(|Z|=\sqrt{25}\)

|Z| = 5 Ω

Important Notes:

For a series RLC circuit, the net impedance is given by:

Z = R + j (XL - XC)

XL = Inductive Reactance given by:

XL = ωL

XC = Capacitive Reactance given by:

\(X_C=\frac{1}{\omega C}\)

The magnitude of the impedance will be:

\(|Z|=\sqrt{R^2+(X_L-X_C)^2}\)

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