A tropical location B is 20 km N15° E of A. Another location C is N45°W of A and S75° W of B. How far (in km) is C from A?

(N15° E denotes a direction 15° east of north.)

Question

Question

This question was previously asked in

CSIR-UGC (NET) Chemical Science: Held on (18 Sept 2022)

Answer 1

Concept:

An equilateral triangle has equal sides and the angle between all the sides is 60^o.

Explanation:

As per the instruction given in the question, the diagram is drawn below and all the angles are marked.
F3 Vinanti Teaching 08.09.23 D1

Now, ∠ A = ∠B = ∠C = 60^o

The tiangle is an equilateral triangle as all three angles of the traingle is 60^o.
As AB = 20 km, CA and BA will also be 20 km.

So,the distance between point C and A is 20 km.