A JFET has the following parameters: V_GS(off) = -8 V: I_DSS = 30 mA, and V_GS = -4 V. The drain current will be:

Question

Question

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MPPGCL JE Electrical 19 March 2019 Shift 2 Official Paper

Answer 1

Concept

The drain current in a JFET is given by:

\(I_D=I_{DSS}({1-{V_{GS}\over V_{P}}})^2\)

where, I_D = Drain current

I_DSS = Saturation drain current

V_GS = Gate -source voltage

V_P = Pinch off voltage

Calculation

Given, V_p = - 8 V

IDSS = 30 mA

VGS = - 4 V

\(I_D=30({1-{-4\over -8}})^2\)

I_D = 7.5 mA