Question
Download Solution PDFA JFET has the following parameters: IDSS = 30 mA, VGS(off) = - 5V, VGS = -4.5 V. Find the value of drain current.
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
In pinch off or saturation region in JFET, drain current is given by Shockley equation and is written as
\({I_D} = {I_{DSS}}{\left( {1 - \frac{{{V_{GS}}}}{{{V_{GS\left( {off} \right)}}}}} \right)^2}\)
Calculation:
Given IDSS = 30 mA
VGS = -4.5 volt
VGS(off) = -5 volt
\({I_D} = 30{\left( {1 - \frac{{ - 4.5}}{{ - 5}}} \right)^2} = 0.3\;mA\)
Last updated on May 29, 2025
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