Question
Download Solution PDFA chord 21 cm long is drawn in a circle of diameter 25 cm. The perpendicular distance of the chord from the centre is:
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFGiven:
Chord = 21cm
Diameter = 25 cm
Concept:
The perpendicular drawn from the center on the chord, bisects the chord in two equal parts.
Pythagoras Theorem:
OA2 = OD2 + AD2
Calculation:
Let AB be the chord of length 21 cm.
⇒ OD be the perpendicular distance
⇒ AO be the radius of the circle
OA2 = OD2 + AD2
⇒ (25/2)2 = OD2 + (21/2)2
⇒ 625/4 = OD2 + 441/4
⇒ OD2 = 625/4 - 441/4 = 184/4 = 46
∴ OD = √46
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