Question
Download Solution PDFComprehension
Let \(y = \sin^{-1} \left( x - \frac{4x^3}{27} \right).\)
What is y equal to?
Answer (Detailed Solution Below)
3sin-1\((\frac{x}{3})\)
Detailed Solution
Download Solution PDFCalculation:
Given,
The function is \( y = \sin^{-1} \left( x - \frac{4x^3}{27} \right) \), and we are tasked with simplifying it.
\( y = \sin^{-1} \left( x - \frac{4x^3}{27} \right) \)
We recognize that we can factor the expression as:
\( x - \frac{4x^3}{27} = \left( \frac{x}{3} \right) \left( 3 - 4 \left( \frac{x}{3} \right)^3 \right) \)
Thus, the function becomes:
\( y = \sin^{-1} \left( \frac{x}{3} \left( 3 - 4 \left( \frac{x}{3} \right)^3 \right) \right) \)
Recognizing that this fits a known identity for inverse trigonometric functions:
\( \sin^{-1}(x) = 3 \sin^{-1} \left( \frac{x}{3} \right) \)
Thus, we can simplify the expression to:
\( y = 3 \sin^{-1} \left( \frac{x}{3} \right) \)
Hence, the correct answer is Option 4.
Last updated on Jul 8, 2025
->UPSC NDA Application Correction Window is open from 7th July to 9th July 2025.
->UPSC had extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.