Question
Download Solution PDFWhat is the geometric mean of 6, 8, 16 and 27?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The geometric mean is defined as the nth root of the product of n numbers.
The geometric mean of a data set \(\rm {\textstyle \left\{a_{1},a_{2},\,\ldots ,\,a_{n}\right\}}\) is given by:
\(\rm GM = \rm {\textstyle \left\{a_{1}\times a_{2}\times\,\ldots \times\,a_{n}\right\}}^{\frac{1}{n}}\)
Calculation:
To Find: Geometric mean of 6, 8, 16 and 27
Here n = 4
Now,
\(\rm GM = \rm ({{6 \times 8 \times 16 \times 27}})^{\frac{1}{4}}\)
\(= \rm ({{2 \times 3 \times 2^3 \times 2^4 \times 3^3}})^{\frac{1}{4}} \\ =(2^8 \times 3^4)^{\frac{1}{4}}\\ = (2^2 \times 3)\\=12\)
Last updated on Jun 18, 2025
->UPSC has extended the UPSC NDA 2 Registration Date till 20th June 2025.
-> A total of 406 vacancies have been announced for NDA 2 Exam 2025.
->The NDA exam date 2025 has been announced. The written examination will be held on 14th September 2025.
-> The selection process for the NDA exam includes a Written Exam and SSB Interview.
-> Candidates who get successful selection under UPSC NDA will get a salary range between Rs. 15,600 to Rs. 39,100.
-> Candidates must go through the NDA previous year question paper. Attempting the NDA mock test is also essential.