Question
Download Solution PDFUnder which of the following cases, the power dissipated in R3 in the circuit shown will increase?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFConcept:
The power dissipated by the resistor is given by:
P = I2R
I = Current flowing across the resistor
R = Resistance of the resistor
The power dissipated by the resistor is directly proportional to the square of the current, i.e.
P ∝ I2
Analysis:
The net current flowing across the circuit is given by:
\(I=\frac{E}{R_{eq}}\)
Req = R1 + R2 + R3 + R4
\(I=\frac{E}{R_1+R_2+R_3+R_4}\)
The power dissipated in R3 is:
PR3 = I2 × R3
\(P_{R3}=(\frac{E}{R_1+R_2+R_3+R_4})^2 \times R_3\)
Observation:
- We observe that the power will decrease with an increase in R1 or R2 or R4.
- With a decrease in E, the power dissipated will decrease.
- It is only when R4 is short-circuited, i.e. when R4 = 0, the power dissipated will increase.
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