Question
Download Solution PDFThree distinct natural numbers chosen at random from 1 to 10. What is the probability that they are consecutive?
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
⇒n(S) = 10C3
Favourable outcomes = (1, 2, 3), (2, 3, 4), (3, 4, 5), (4, 5, 6), (5, 6, 7), (6, 7, 8), (7, 8, 9), (8, 9, 10)
⇒n(E) = 8
⇒ P(E) = \(\frac{n(E)}{n(S)} = \frac{8}{^{10}C_3}\)
= \(\frac{8\times3\times2\times1}{10\times9 \times8} =\frac{1}{15}\)
∴ Option (c) is correct
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