The resulting current through the circuit is:(Assuming non-ideal diode)

Concept:

At forward bias condition → Diode should be replaced with a battery source of value equal to its barrier potential(for silicon 0.7 V)circuit and the equivalent forward resistance rf (assume zero if not given)

At reverse bias condition → Diode should be replaced with an open circuit.

Calculation:

In the circuit arrangement diode is in forward bias;

Then;

\(I_{D} = \frac{10-0.7+5}{4.7+2.2} = 2.07 \, mA\)