The peak voltage of the ac source is equal to:

  1. \(1/\sqrt{2}\)  times the rms value of the ac source
  2. the value of voltage supplied to the circuit
  3. the rms value of the ac source
  4. \(\sqrt{2}\) times the rms value of the ac source

Answer (Detailed Solution Below)

Option 4 : \(\sqrt{2}\) times the rms value of the ac source
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Detailed Solution

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Concept:

Peak voltage of an AC source is the highest point or highest value of the voltage in case of any voltage waveform.

Root mean square value or rms value of voltage of an AC source is the value which is the most efficient value of the total waveform. 

Peak voltage = √2 × RMS value of voltage

Calculation:

Peak voltage of the ac source is equal to  √2 × RMS value of voltage of the AC source.

Hence, option (4) is the correct answer.

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