Question
Download Solution PDFThe objective function z = 3X1 + 5x2 is to be maximized subject to constraints
X1 + 2x2 ≤ 200
X1 + x2 ≤ 150
X1, x2 ≤ 0
The values of x1 and x2 in this context are, respectively
Answer (Detailed Solution Below)
Detailed Solution
Download Solution PDFExplanation:
So,
At x1 = 100 and x2 = 50
z = 3(100) + 5(50)
z = 300 + 250
z = 550
Unique optimal solutional
∴ x1 = 100 and x2 = 50 , zmax = 150
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