The binding energy of the deuterium is 2.23 MeV. The mass defect in amu is

  1. 0.0024
  2. 0.0012
  3. 2.23
  4. 0.024

Answer (Detailed Solution Below)

Option 1 : 0.0024
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CONCEPT:

  • Binding Energy: The energy needed to break a nucleus into its constituent protons and neutrons.
  • Binding energy per nucleon (BEN)Energy needs to remove a nucleon from a nucleus.
  • Mass defectDifference between the mass of a nucleus and the total mass of its constituent nucleons.

F1 J.K Madhu 19.05.20 D17

Binding Energy (B) = Δm × 931 MeV 

Where Δm = mass defect.

CALCULATION:

Given - Binding Energy (B) = 2.23 MeV

The mass defect in amu is

⇒ B = Δm × 931 MeV 

\(\Rightarrow \Delta m = \frac{2.23}{931}=0.0024\, \, amu\)

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