12tan A = 5 అయితే, cosec A =?

A. 13/5

B. 12/13

C. 5/13

D. 12/5

This question was previously asked in
NTPC Tier I (Held On: 5 Apr 2016 Shift 1)
View all RRB NTPC Papers >
  1. B
  2. C
  3. A
  4. D

Answer (Detailed Solution Below)

Option 3 : A
Free
RRB NTPC CBT-I Official Paper (Held On: 4 Jan 2021 Shift 1)
5.5 Lakh Users
100 Questions 100 Marks 90 Mins

Detailed Solution

Download Solution PDF

ఇచ్చినది:

12tan A = 5

ఉపయోగించిన భావన:

త్రికోణమితి నిష్పత్తుల భావనను ఉపయోగించి,

tanθ = లంబం/ఆధారం

cosecθ = కర్ణం/ లంబం

గణన:

quesImage4072

12tanA = 5

⇒ tanA = 5/12

tanA = BC/AB

BC/AB = 5/12

ΔABC లో,

పైథాగరస్ సిద్ధాంతాన్ని ఉపయోగించి,

BC2 + AB2 = AC2

⇒ 52 + 122 = AC2

⇒ 25 + 144 = AC2

⇒ AC = √169

⇒ AC = 13

cosecA = AC/BC

⇒ cosecA = 13/5

cosecA విలువ 13/5.

Latest RRB NTPC Updates

Last updated on Jun 23, 2025

-> RRB NTPC Exam Analysis 2025 is LIVE now. All the candidates appearing for the RRB NTPC Exam 2025 can check the complete exam analysis to strategize their preparation accordingly. 

-> The RRB NTPC Admit Card 2025 has been released on its official website.

-> Candidates who will appear for the RRB NTPC Exam can check their RRB NTPC Time Table 2025 from here.

-> The RRB NTPC CBT 1 Exam is scheduled from 5th June to 24th June 2025 as per the revised tentative exam schedule. 

-> The RRB NTPC 2025 Notification has been released for a total of 11558 vacancies.

-> A total of 3445 Vacancies have been announced for Undergraduate posts like Commercial Cum Ticket Clerk, Accounts Clerk Cum Typist, Junior Clerk cum Typist & Trains Clerk.

-> A total of 8114 vacancies are announced for Graduate-level posts in the Non-Technical Popular Categories (NTPC) such as Junior Clerk cum Typist, Accounts Clerk cum Typist, Station Master, etc.

-> Prepare for the exam using RRB NTPC Previous Year Papers.

Get Free Access Now
Hot Links: teen patti gold apk download teen patti 500 bonus teen patti master 51 bonus