Ripple factor of a half wave rectifier is:

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  1. 1.21
  2. 0.08
  3. 0.61
  4. 2.14

Answer (Detailed Solution Below)

Option 1 : 1.21
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Detailed Solution

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CONCEPT:

Ripple

  • ‘Ripple’ is the unwanted AC component remaining when converting the AC voltage waveform into a DC waveform. Even though we try our best to remove all AC components, there is still some small amount left on the output side which pulsates the DC waveform. This undesirable AC component is called a ‘ripple’.

Ripple factor

  • The ripple factor is the ratio between the RMS value of the AC voltage (on the input side) and the DC voltage (on the output side) of the rectifier.

\(\Rightarrow r=\frac{\sqrt{I_{rms}^{2}-I_{dc}^{2}}}{I_{dc}}\)     -----(1)

CALCULATION:

Given \(I_{rms}=\frac{I_{o}}{\sqrt{2}}\) and \( I_{dc}=\frac{I_{o}}{\pi}\)

  • rectifier is a device that converts an alternating current into a direct current. A p-n junction can be used as a rectifier because it permits current in one direction only.
  • p-n junction can be used as a rectifier because it permits current in one direction only.

By equation 1,

\(\Rightarrow r=\frac{\sqrt{I_{rms}^{2}-I_{dc}^{2}}}{I_{dc}}\)

\(\Rightarrow I_{rms}=\frac{\sqrt{\frac{I_{o}^{2}}{2}-\frac{I_{o}^{2}}{\pi^{2}}}}{\frac{I_{o}}{\pi}}\) = 1.21

  • Hence, option 1 is correct.

Additional Information

CIRCUIT DIAGRAM

Ripple factor

F1 S.B Madhu 20.01.20 D1

Half-Wave Rectifier

1.21

Diagram DMRC

      Center-Tap Full Wave Rectifier

0.48

F1 S.B Madhu 20.01.20 D3

Bridge-Type Full Wave Rectifier

0.48

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